Hamiltonian vector field

In mathematics and physics, a Hamiltonian vector field on a symplectic manifold is a vector field defined for any energy function or Hamiltonian. Named after the physicist and mathematician Sir William Rowan Hamilton, a Hamiltonian vector field is a geometric manifestation of Hamilton's equations in classical mechanics. The integral curves of a Hamiltonian vector field represent solutions to the equations of motion in the Hamiltonian form. The diffeomorphisms of a symplectic manifold arising from the flow of a Hamiltonian vector field are known as canonical transformations in physics and (Hamiltonian) symplectomorphisms in mathematics.[1]

Hamiltonian vector fields can be defined more generally on an arbitrary Poisson manifold. The Lie bracket of two Hamiltonian vector fields corresponding to functions f{\displaystyle f} and g{\displaystyle g} on the manifold is itself a Hamiltonian vector field, with the Hamiltonian given by the Poisson bracket of f{\displaystyle f} and g{\displaystyle g}.

Definition

Suppose that (M,ω){\displaystyle (M,\omega )} is a symplectic manifold. Since the symplectic formω{\displaystyle \omega } is nondegenerate, it sets up a fiberwise-linearisomorphism

ω:TMTM,{\displaystyle \omega :TM\to T^{*}M,}

between the tangent bundleTM{\displaystyle TM} and the cotangent bundleTM{\displaystyle T^{*}M}, with the inverse

Ω:TMTM,Ω=ω1.{\displaystyle \Omega :T^{*}M\to TM,\quad \Omega =\omega ^{-1}.}

Therefore, one-forms on a symplectic manifold M{\displaystyle M} may be identified with vector fields and every differentiable functionH:MR{\displaystyle H:M\rightarrow \mathbb {R} } determines a unique vector fieldXH{\displaystyle X_{H}}, called the Hamiltonian vector field with the HamiltonianH{\displaystyle H}, by defining for every vector field Y{\displaystyle Y} on M{\displaystyle M},

dH(Y)=ω(XH,Y).{\displaystyle \mathrm {d} H(Y)=\omega (X_{H},Y).}Or more succinctly, ιXHω=dH{\displaystyle \iota _{X_{H}}\omega =dH}.

Note: Some authors define the Hamiltonian vector field with the opposite sign. One has to be mindful of varying conventions in physical and mathematical literature.

Examples

Suppose that M{\displaystyle M} is a 2n{\displaystyle 2n}-dimensional symplectic manifold. Then locally, one may choose canonical coordinates(q1,,qn,p1,,pn){\displaystyle (q^{1},\cdots ,q^{n},p_{1},\cdots ,p_{n})} on M{\displaystyle M}, in which the symplectic form is expressed as:[2]ω=idqidpi,{\displaystyle \omega =\sum _{i}\mathrm {d} q^{i}\wedge \mathrm {d} p_{i},}

where d{\displaystyle \operatorname {d} } denotes the exterior derivative and {\displaystyle \wedge } denotes the exterior product. Then the Hamiltonian vector field with Hamiltonian H{\displaystyle H} takes the form:[1]XH=(Hpi,Hqi)=ΩdH,{\displaystyle \mathrm {X} _{H}=\left({\frac {\partial H}{\partial p_{i}}},-{\frac {\partial H}{\partial q^{i}}}\right)=\Omega \,\mathrm {d} H,}

where Ω{\displaystyle \Omega } is a 2n×2n{\displaystyle 2n\times 2n} square matrix

Ω=[0InIn0],{\displaystyle \Omega ={\begin{bmatrix}0&I_{n}\\-I_{n}&0\\\end{bmatrix}},}

and

dH=[HqiHpi].{\displaystyle \mathrm {d} H={\begin{bmatrix}{\frac {\partial H}{\partial q^{i}}}\\{\frac {\partial H}{\partial p_{i}}}\end{bmatrix}}.}

The matrix Ω{\displaystyle \Omega } is frequently denoted with J{\displaystyle \mathbf {J} }.

Suppose that M=R2n{\displaystyle M=\mathbb {R} ^{2n}} is the 2n{\displaystyle 2n}-dimensional symplectic vector space with (global) canonical coordinates.

  • If H=pi{\displaystyle H=p_{i}} then XH=/qi;{\displaystyle X_{H}=\partial /\partial q^{i};}
  • if H=qi{\displaystyle H=q_{i}} then XH=/pi;{\displaystyle X_{H}=-\partial /\partial p^{i};}
  • if H=12(pi)2{\textstyle H={\frac {1}{2}}\sum (p_{i})^{2}} then XH=pi/qi;{\textstyle X_{H}=\sum p_{i}\partial /\partial q^{i};}
  • if H=12aijqiqj,aij=aji{\textstyle H={\frac {1}{2}}\sum a_{ij}q^{i}q^{j},a_{ij}=a_{ji}} then XH=aijqi/pj.{\textstyle X_{H}=-\sum a_{ij}q_{i}\partial /\partial p^{j}.}

Properties

  • The assignment fXf{\displaystyle f\mapsto X_{f}} is linear, so that the sum of two Hamiltonian functions transforms into the sum of the corresponding Hamiltonian vector fields.
  • Suppose that (q1,,qn,p1,,pn){\displaystyle (q^{1},\cdots ,q^{n},p_{1},\cdots ,p_{n})} are canonical coordinates on M{\displaystyle M} (see above). Then a curve γ(t)=(q(t),p(t)){\displaystyle \gamma (t)=(q(t),p(t))} is an integral curve of the Hamiltonian vector field XH{\displaystyle X_{H}}if and only if it is a solution of Hamilton's equations:[1]q˙i=Hpip˙i=Hqi.{\displaystyle {\begin{aligned}{\dot {q}}^{i}&={\frac {\partial H}{\partial p_{i}}}\\{\dot {p}}_{i}&=-{\frac {\partial H}{\partial q^{i}}}.\end{aligned}}}
  • The Hamiltonian H{\displaystyle H} is constant along the integral curves, because dH,γ˙=ω(XH(γ),XH(γ))=0{\displaystyle \langle dH,{\dot {\gamma }}\rangle =\omega (X_{H}(\gamma ),X_{H}(\gamma ))=0}. That is, H(γ(t)){\displaystyle H(\gamma (t))} is actually independent of t{\displaystyle t}. This property corresponds to the conservation of energy in Hamiltonian mechanics.
  • More generally, if two functions F{\displaystyle F} and H{\displaystyle H} have a zero Poisson bracket (cf. below), then F{\displaystyle F} is constant along the integral curves of H{\displaystyle H}, and similarly, H{\displaystyle H} is constant along the integral curves of F{\displaystyle F}. This fact is the abstract mathematical principle behind Noether's theorem.[nb 1]
  • The symplectic formω{\displaystyle \omega } is preserved by the Hamiltonian flow. Equivalently, the Lie derivativeLXHω=0{\displaystyle {\mathcal {L}}_{X_{H}}\omega =0}.

Poisson bracket

The notion of a Hamiltonian vector field leads to a skew-symmetric bilinear operation on the differentiable functions on a symplectic manifold M{\displaystyle M}, the Poisson bracket, defined by the formula

{f,g}=ω(Xg,Xf)=dg(Xf)=LXfg{\displaystyle \{f,g\}=\omega (X_{g},X_{f})=dg(X_{f})={\mathcal {L}}_{X_{f}}g}

where LX{\displaystyle {\mathcal {L}}_{X}} denotes the Lie derivative along a vector field X{\displaystyle X}. Moreover, one can check that the following identity holds:[1]X{f,g}=[Xf,Xg]{\displaystyle X_{\{f,g\}}=-[X_{f},X_{g}]},

where the right hand side represents the Lie bracket of the Hamiltonian vector fields with Hamiltonians f{\displaystyle f} and g{\displaystyle g}. As a consequence (a proof at Poisson bracket), the Poisson bracket satisfies the Jacobi identity:[1]{{f,g},h}+{{g,h},f}+{{h,f},g}=0{\displaystyle \{\{f,g\},h\}+\{\{g,h\},f\}+\{\{h,f\},g\}=0},

which means that the vector space of differentiable functions on M{\displaystyle M}, endowed with the Poisson bracket, has the structure of a Lie algebra over R{\displaystyle \mathbb {R} }, and the assignment fXf{\displaystyle f\mapsto X_{f}} is a Lie algebra homomorphism, whose kernel consists of the locally constant functions (constant functions if M{\displaystyle M} is connected).

Remarks

  1. See Lee (2003, Chapter 18) for a very concise statement and proof of Noether's theorem.

Notes

  1. 12345Lee 2003, Chapter 18.
  2. Lee 2003, Chapter 12.

Works cited